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-7d^2+d+9=0
a = -7; b = 1; c = +9;
Δ = b2-4ac
Δ = 12-4·(-7)·9
Δ = 253
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{253}}{2*-7}=\frac{-1-\sqrt{253}}{-14} $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{253}}{2*-7}=\frac{-1+\sqrt{253}}{-14} $
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